$$600\,cc$$  of a gas at a pressure of $$750\,mm$$  is compressed to $$500\,cc.$$  Taking the temperature to remain constant, the increase in pressure is

Solution :
$$\eqalign{ & {\text{According to Boyle's law,}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,{p_1}{V_1} = {p_2}{V_2} \cr & 750 \times 600 = {p_2} \times 500 \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,{p_2} = \frac{{750 \times 600}}{{500}} \cr & \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, = 900\,mm \cr & {\text{So, the increase in pressure}} \cr & = 900 - 750 \cr & = 150\,mm \cr} $$