Question
$$18.72\,g$$ of a substance $$'X'$$ occupies $$1.81\,c{m^3}.$$ What will be its density measured in correct Significant figures ?
A.
$$10.3\,g\,c{m^{ - 3}}$$
B.
$$10.34\,g\,c{m^{ - 3}}$$
C.
$$10.4\,g\,c{m^{ - 3}}$$
D.
$$10.3425\,g\,c{m^{ - 3}}$$
Answer :
$$10.3\,g\,c{m^{ - 3}}$$
Solution :
$${\text{Density}} = \frac{{{\text{Mass}}}}{{{\text{Volume}}}} = \frac{{18.72}}{{1.81}} = 10.34\,g\,c{m^{ - 3}}$$
Since volume contains 3 significant figures hence, answer will be $$10.3\,g\,c{m^{ - 3}}.$$