$$0.92\,g$$ of an organic compound was analysed by combustion method. The mass of the $$U$$ - tube increased by $$1.08\,g.$$ What is the percentage of hydrogen in the compound?
A.
$$13.04\% $$
B.
$$52.17\% $$
C.
$$65.21\% $$
D.
$$11.30\% $$
Answer :
$$13.04\% $$
Solution :
$$\eqalign{
& {\text{Increase in mass of }}U{\text{ - tube}} = 1.08\,g \cr
& {\text{Mass of water formed}} = 1.08\,g \cr
& 18\,g\,{H_2}O \equiv 2\,g\,H \cr
& 1.08\,g\,{H_2}O = \frac{2}{{18}} \times 1.08 \cr} $$
$$\% \,{\text{ of hydrogen }} = \frac{2}{{18}} \times \frac{{1.08}}{{0.92}} \times 100$$ $$ = 13.04\% $$
Releted MCQ Question on Organic Chemistry >> General Organic Chemistry
Releted Question 1
The bond order of individual carbon-carbon bonds in
benzene is