Which of the following graphs correctly represents the variation $$\beta = - \frac{{\frac{{dV}}{{dP}}}}{V}$$ with $$P$$ for an ideal gas at constant temperature ?
A.
B.
C.
D.
Answer :
Solution :
$$PV$$ = constant. Differentiating,
$$\eqalign{
& \frac{{P\,dV}}{{dP}} = - V;\beta \cr
& = - \left( {\frac{1}{V}} \right)\left( {\frac{{dV}}{{dP}}} \right) \cr
& = \left( {\frac{1}{P}} \right) \cr
& \Rightarrow \,\,\beta \times P = 1 \cr} $$
∴ Graph between $$\beta $$ and $$P$$ will be a rectangular hyperbola.
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