Question
Two rigid boxes containing different ideal gases are placed on a table. Box contains one mole of nitrogen at temperature $${T_0},$$ while Box contains one mole of helium at temperature $$\left( {\frac{7}{3}} \right){T_0}.$$ The boxes are then put into thermal contact with each other, and heat flows between them until the gases reach a common final temperature (ignore the heat capacity of boxes). Then, the final temperature of the gases, $${T_f}$$ in terms of $${T_0}$$ is
A.
$${T_f} = \frac{3}{7}{T_0}$$
B.
$${T_f} = \frac{7}{3}{T_0}$$
C.
$${T_f} = \frac{3}{2}{T_0}$$
D.
$${T_f} = \frac{5}{2}{T_0}$$
Answer :
$${T_f} = \frac{3}{2}{T_0}$$
Solution :
Heat lost by $$He$$ = Heat gained by $${N_2}$$
$$\eqalign{
& {n_1}{C_{{v_1}}}\Delta {T_1} = {n_2}{C_{{v_2}}}\Delta {T_2} \cr
& \frac{3}{2}R\left[ {\frac{7}{3}{T_0} - {T_f}} \right] = \frac{5}{2}R\left[ {{T_f} - {T_0}} \right] \cr
& \Rightarrow \,\,{T_f} = \frac{3}{2}{T_0} \cr} $$