Two particles $$P$$ and $$Q$$ simultaneously start moving from point $$A$$ with velocities $$15\,m/s$$ and $$20\,m/s$$ respectively. The two particles move with acceleration equal in magnitude but opposite in direction. When $$P$$ overtakes $$Q$$ at $$B$$ then its velocity is $$30\,m/s$$ The velocity of $$Q$$ at point $$B$$ will be
A.
$$30\,m/s$$
B.
$$5\,m/s$$
C.
$$20\,m/s$$
D.
$$15\,m/s$$
Answer :
$$5\,m/s$$
Solution :
As magnitude of acceleration is same $$\frac{{30 - 15}}{t} = \frac{{20 - {V_Q}}}{t}$$
$$15 = 20 - {V_Q} \Rightarrow {V_Q} = 5\,m/s$$
Releted MCQ Question on Basic Physics >> Kinematics
Releted Question 1
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