Two cities are $$150\,km$$ apart. Electric power is sent from one city to another city through copper wires. The fall of potential per $$km$$ is $$8$$ volt and the average resistance per $$km$$ is $$0.5\,\Omega .$$ The power loss in the wires is :
A.
$$19.2\,W$$
B.
$$19.2\,kW$$
C.
$$19.2\,J$$
D.
$$12.2\,kW$$
Answer :
$$19.2\,kW$$
Solution :
Total resistance $$R = \left( {0.5\,\Omega /km} \right) \times \left( {150\,km} \right) = 75\,\Omega $$
Total voltage drop $$ = \left( {8\,V/km} \right) \times \left( {150\,km} \right) = 1200\,V$$
Power loss $$ = \frac{{{{\left( {\Delta V} \right)}^2}}}{R} = \frac{{{{\left( {1200} \right)}^2}}}{{75}}W$$
$$\eqalign{
& = 19200\,W \cr
& = 19.2\,kW \cr} $$
Releted MCQ Question on Electrostatics and Magnetism >> Electric Current
Releted Question 1
The temperature coefficient of resistance of a wire is 0.00125 per $$^ \circ C$$ At $$300\,K,$$ its resistance is $$1\,ohm.$$ This resistance of the wire will be $$2\,ohm$$ at.
The electrostatic field due to a point charge depends on the distance $$r$$ as $$\frac{1}{{{r^2}}}.$$ Indicate which of the following quantities shows same dependence on $$r.$$
A.
Intensity of light from a point source.
B.
Electrostatic potential due to a point charge.
C.
Electrostatic potential at a distance r from the centre of a charged metallic sphere. Given $$r$$ < radius of the sphere.