The self inductance of the motor of an electric fan is $$10 H.$$ In order to impart maximum power at $$50 Hz,$$ it should be connected to a capacitance of
A.
$$8\mu F$$
B.
$$4\mu F$$
C.
$$2\mu F$$
D.
$$1\mu F$$
Answer :
$$1\mu F$$
Solution :
For maximum power, $${X_L} = {X_C},$$ which yields
$$\eqalign{
& C = \frac{1}{{{{\left( {2\pi n} \right)}^2}L}} = \frac{1}{{4{\pi ^2} \times 50 \times 50 \times 10}} \cr
& \therefore C = 0.1 \times {10^{ - 5}}F = 1\mu F \cr} $$
Releted MCQ Question on Electrostatics and Magnetism >> Alternating Current
Releted Question 1
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An $$AC$$ voltage source of variable angular frequency $$\omega $$ and fixed amplitude $${V_0}$$ is connected in series with a capacitance $$C$$ and an electric bulb of resistance $$R$$ (inductance zero). When $$\omega $$ is increase
In a transformer, number of turns in the primary coil are 140
and that in the secondary coil are 280. If current in primary coil is $$4A,$$ then that in the secondary coil is