The period of moon's rotation around the earth is nearly 29 days. If moon's mass were 2 fold its present value and all other things remain unchanged, the period of moon's rotation would be nearly
A.
$$29\sqrt 2 \,{\text{days}}$$
B.
$$\frac{{29}}{{\sqrt 2 }}\,{\text{days}}$$
C.
$$29 \times 2\,{\text{days}}$$
D.
$$29\,{\text{days}}$$
Answer :
$$29\,{\text{days}}$$
Solution :
Time period does not depend upon the mass of satellite
Releted MCQ Question on Basic Physics >> Gravitation
Releted Question 1
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