The nuclei $$_6{C^{13}}$$ and $$_7{N^{14}}$$ can be described as
A.
isotones
B.
isobars
C.
isotopes of carbon
D.
isotopes of nitrogen
Answer :
isotones
Solution :
Isotones are the nuclides which contain the same number of neutrons. In $$_6{C^{13}}$$ and $$_7{N^{14}},$$ number of neutrons in carbon $$= 13 - 6 = 7$$ and number of neutrons in nitrogen $$= 14 - 7 = 7.$$ NOTE
No. of neutrons is given by mass no. $$\left( A \right) - $$ atomic no. $$\left( Z \right)$$
Releted MCQ Question on Modern Physics >> Atoms or Nuclear Fission and Fusion
In the nuclear fusion reaction
$$_1^2H + _1^3H \to _2^4He + n$$
given that the repulsive potential energy between the two
nuclei is $$ \sim 7.7 \times {10^{ - 14}}J,$$ the temperature at which the gases must be heated to initiate the reaction is nearly
[Boltzmann’s Constant $$k = 1.38 \times {10^{ - 23}}J/K$$ ]
The binding energy per nucleon of deuteron $$\left( {_1^2H} \right)$$ and helium nucleus $$\left( {_2^4He} \right)$$ is $$1.1\,MeV$$ and $$7\,MeV$$ respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is