Question
The circuit shown here has two batteries of $$8.0\,V$$ and $$16.0\,V$$ and three resistors $$3\,\Omega ,9\,\Omega $$ and $$9\,\Omega $$ and a capacitor of $$5.0\,\mu F.$$
The circuit shown here has two batteries of $$8.0\,V$$ and $$16.0\,V$$ and three resistors $$3\,\Omega ,9\,\Omega $$ and $$9\,\Omega $$ and a capacitor of $$5.0\,\mu F.$$
How much is the current $$I$$ in the circuit in steady state?
A.
$$1.6\,A$$
B.
$$0.67\,A$$
C.
$$2.5\,A$$
D.
$$0.25\,A$$
Answer :
$$0.67\,A$$
Solution :
In steady state capacitor is fully charged hence no current will flow through line 2.
By simplyfing the circuit
Hence resultant potential difference across resistances will be $$8.0\,V.$$
Thus current $$I = \frac{V}{R} = \frac{{8.0}}{{3 + 9}} = \frac{8}{{12}}$$
$${\text{or,}}\,I = \frac{2}{3} = 0.67\,A$$
In steady state capacitor is fully charged hence no current will flow through line 2.
By simplyfing the circuit
Hence resultant potential difference across resistances will be $$8.0\,V.$$
Thus current $$I = \frac{V}{R} = \frac{{8.0}}{{3 + 9}} = \frac{8}{{12}}$$
$${\text{or,}}\,I = \frac{2}{3} = 0.67\,A$$
