Question

Statement-1: The point $$A\left( {1,\,0,\,7} \right)$$   is the mirror image of the point $$B\left( {1,\,6,\,3} \right)$$   in the line : $$\frac{x}{1} = \frac{{y - 1}}{2} = \frac{{z - 2}}{3}$$
Statement-2: The line : $$\frac{x}{1} = \frac{{y - 1}}{2} = \frac{{z - 2}}{3}$$     bisects the line segment joining $$A\left( {1,\,0,\,7} \right)$$   and $$B\left( {1,\,6,\,3} \right).$$

A. Statement-1 is true, Statement-2 is true ; Statement-2 is not a correct explanation for Statement-1.  
B. Statement-1 is true, Statement-2 is false.
C. Statement-1 is false, Statement-2 is true.
D. Statement-1 is true, Statement-2 is true ; Statement-2 is a correct explanation for Statement-1.
Answer :   Statement-1 is true, Statement-2 is true ; Statement-2 is not a correct explanation for Statement-1.
Solution :
The direction ratios of the line segment joining points $$A\left( {1,\,0,\,7} \right)$$   and $$B\left( {1,\,6,\,3} \right)$$   are $$0,\, 6,\,-4.$$
The direction ratios of the given line are $$1, \,2, \,3.$$
Clearly $$1 \times 0 + 2 \times 6 + 3 \times \left( { - 4} \right) = 0$$
So, the given line is perpendicular to line $$AB.$$
Also , the mid point of $$A$$ and $$B$$ is $$\left( {1,\,3,\,5} \right)$$  which lies on the given line.
So, the image of $$B$$ in the given line is $$A,$$  because the given line is the perpendicular bisector of line segment joining points $$A$$ and $$B,$$  But statement-2 is not a correct explanation for statement-1.

Releted MCQ Question on
Geometry >> Three Dimensional Geometry

Releted Question 1

The value of $$k$$ such that $$\frac{{x - 4}}{1} = \frac{{y - 2}}{1} = \frac{{z - k}}{2}$$     lies in the plane $$2x - 4y + z = 7,$$    is :

A. $$7$$
B. $$ - 7$$
C. no real value
D. $$4$$
Releted Question 2

If the lines $$\frac{{x - 1}}{2} = \frac{{y + 1}}{3} = \frac{{z - 1}}{4}$$      and $$\frac{{x - 3}}{1} = \frac{{y - k}}{2} = \frac{z}{1}$$     intersect, then the value of $$k$$ is :

A. $$\frac{3}{2}$$
B. $$\frac{9}{2}$$
C. $$ - \frac{2}{9}$$
D. $$ - \frac{3}{2}$$
Releted Question 3

A plane which is perpendicular to two planes $$2x - 2y + z = 0$$    and $$x - y + 2z = 4,$$    passes through $$\left( {1,\, - 2,\,1} \right).$$   The distance of the plane from the point $$\left( {1,\,2,\,2} \right)$$  is :

A. $$0$$
B. $$1$$
C. $$\sqrt 2 $$
D. $$2\sqrt 2 $$
Releted Question 4

Let $$P\left( {3,\,2,\,6} \right)$$   be a point in space and $$Q$$ be a point on the line $$\vec r = \left( {\hat i - \hat j + 2\hat k} \right) + \mu \left( { - 3\hat i + \hat j + 5\hat k} \right)$$
Then the value of $$\mu $$ for which the vector $$\overrightarrow {PQ} $$  is parallel to the plane $$x-4y+3z=1$$    is :

A. $$\frac{1}{4}$$
B. $$ - \frac{1}{4}$$
C. $$\frac{1}{8}$$
D. $$ - \frac{1}{8}$$

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Three Dimensional Geometry


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