Question
In producing chlorine by electrolysis $$100\,kW$$ power at $$125\,V$$ is being consumed. How much chlorine per minute is liberated (ECE of chlorine is $$0.367 \times {10^{ - 6}}kg\,{C^{ - 1}}$$ )
A.
$$1.76 \times {10^{ - 3}}kg$$
B.
$$9.67 \times {10^{ - 3}}kg$$
C.
$$17.61 \times {10^{ - 3}}kg$$
D.
$$3.67 \times {10^{ - 3}}kg$$
Answer :
$$17.61 \times {10^{ - 3}}kg$$
Solution :
Mass of the substance deposited at the cathode is given by
$$m = Zit$$ ($$Z =$$ electrochemical equivalent)
$$\eqalign{
& = Z\left( {\frac{W}{V}} \right)t = 0.367 \times {10^{ - 6}} \times \frac{{100 \times {{10}^3}}}{{125}} \times 60 \cr
& = 17.6 \times {10^{ - 3}}kg \cr} $$