in nuclear fission process energy is released because

In nuclear fission process, energy is released because

A. mass of products is more than mass of nucleus

B. total binding energy of products formed due to nuclear fission is more than the parent fissionable material

C. total binding energy of products formed due to nuclear fission is less than parent fissionable material

D. mass of some particles is converted into energy

Answer : total binding energy of products formed due to nuclear fission is more than the parent fissionable material

Solution :
In a nuclear process, energy is released if binding energy per nucleon of the daughter products gets increased. In nuclear fission reaction, total binding energy of products formed due to nuclear fission is more than the parent fissionable material.

Releted MCQ Question on
Modern Physics >> Atoms or Nuclear Fission and Fusion

Releted Question 1

The equation
$$4_1^1{H^ + } \to _2^4H{e^{2 + }} + 2{e^ - } + 26MeV$$ represents

A. $$\beta $$ -decay

B. $$\gamma $$ -decay

C. fusion

D. fission

View Answer

Releted Question 2

Fast neutrons can easily be slowed down by

A. the use of lead shielding

B. passing them through water

C. elastic collisions with heavy nuclei

D. applying a strong electric field

View Answer

Releted Question 3

In the nuclear fusion reaction
$$_1^2H + _1^3H \to _2^4He + n$$
given that the repulsive potential energy between the two nuclei is $$ \sim 7.7 \times {10^{ - 14}}J,$$ the temperature at which the gases must be heated to initiate the reaction is nearly
[Boltzmann’s Constant $$k = 1.38 \times {10^{ - 23}}J/K$$ ]

A. $${10^7}K$$

B. $${10^5}K$$

C. $${10^3}K$$

D. $${10^9}K$$

View Answer

Releted Question 4

The binding energy per nucleon of deuteron $$\left( {_1^2H} \right)$$ and helium nucleus $$\left( {_2^4He} \right)$$ is $$1.1\,MeV$$ and $$7\,MeV$$ respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

A. $$23.6\,MeV$$

B. $$26.9\,MeV$$

C. $$13.9\,MeV$$

D. $$19.2\,MeV$$

View Answer

In nuclear fission process, energy is released because

Releted MCQ Question on
Modern Physics >> Atoms or Nuclear Fission and Fusion

The equation
$$4_1^1{H^ + } \to _2^4H{e^{2 + }} + 2{e^ - } + 26MeV$$ represents

Fast neutrons can easily be slowed down by

The binding energy per nucleon of deuteron $$\left( {_1^2H} \right)$$ and helium nucleus $$\left( {_2^4He} \right)$$ is $$1.1\,MeV$$ and $$7\,MeV$$ respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

Practice More Releted MCQ Question on
Atoms or Nuclear Fission and Fusion

Practice More MCQ Question on Physics Section

In nuclear fission process, energy is released because

Releted MCQ Question on Modern Physics >> Atoms or Nuclear Fission and Fusion

The equation $$4_1^1{H^ + } \to _2^4H{e^{2 + }} + 2{e^ - } + 26MeV$$ represents

Fast neutrons can easily be slowed down by

The binding energy per nucleon of deuteron $$\left( {_1^2H} \right)$$ and helium nucleus $$\left( {_2^4He} \right)$$ is $$1.1\,MeV$$ and $$7\,MeV$$ respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is

Practice More Releted MCQ Question on Atoms or Nuclear Fission and Fusion

Practice More MCQ Question on Physics Section

Releted MCQ Question on
Modern Physics >> Atoms or Nuclear Fission and Fusion

The equation
$$4_1^1{H^ + } \to _2^4H{e^{2 + }} + 2{e^ - } + 26MeV$$ represents

Practice More Releted MCQ Question on
Atoms or Nuclear Fission and Fusion