In given $$RC$$ circuit, capacitance of capacitor $${C_1} = 3\mu F$$ and $${C_2} = 1\mu F.$$ It is given that time constant of circuit between $$A$$ and $$B$$ is 3 millisecond. Value of $$R$$ will be
A.
$$1\Omega $$
B.
$$10\Omega $$
C.
$$100\Omega $$
D.
$$1000\Omega $$
Answer :
$$1000\Omega $$
Solution :
Equivalent circuit can be drawn as below
$$\eqalign{
& RC = 3 \times {10^{ - 3}}\sec \cr
& R \times 3 \times {10^{ - 6}} = 3 \times {10^{ - 3}} \cr
& R = 1000\Omega \cr} $$
Releted MCQ Question on Electrostatics and Magnetism >> Alternating Current
Releted Question 1
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