Question

In a Young’s double slit experiment, $$12$$ fringes are observed to be formed in a certain segment of the screen when light of wavelength $$600\,nm$$   is used. If the wavelength of light is changed to $$400\,nm,$$   number of fringes observed in the same segment of the screen is given by

A. 12
B. 18  
C. 24
D. 30
Answer :   18
Solution :
$$\frac{{12{\lambda _1}D}}{d} = \frac{{k{\lambda _2}D}}{d},k = \frac{{12 \times 600}}{{400}} = 18$$

Releted MCQ Question on
Optics and Wave >> Wave Optics

Releted Question 1

In Young’s double-slit experiment, the separation between the slits is halved and the distance between the slits and the screen is doubled. The fringe width is

A. unchanged.
B. halved
C. doubled
D. quadrupled
Releted Question 2

Two coherent monochromatic light beams of intensities $$I$$ and $$4\,I$$  are superposed. The maximum and minimum possible intensities in the resulting beam are

A. $$5\,I$$  and $$I$$
B. $$5\,I$$  and $$3\,I$$
C. $$9\,I$$  and $$I$$
D. $$9\,I$$  and $$3\,I$$
Releted Question 3

A beam of light of wave length $$600\,nm$$  from a distance source falls on a single slit $$1mm$$  wide and a resulting diffraction pattern is observed on a screen $$2\,m$$  away. The distance between the first dark fringes on either side of central bright fringe is

A. $$1.2\,cm$$
B. $$1.2\,mm$$
C. $$2.4\,cm$$
D. $$2.4\,mm$$
Releted Question 4

Consider Fraunh offer diffraction pattern obtained with a single slit illuminated at normal incidence. At the angular position of the first diffraction minimum the phase difference (in radians) between the wavelets from the opposite edges of the slit is

A. $$\frac{\pi }{4}$$
B. $$\frac{\pi }{2}$$
C. $$2\,\pi $$
D. $$\pi $$

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