Question

In a simple harmonic oscillator, at the mean position

A. kinetic energy is minimum, potential energy is maximum

B. both kinetic and potential energies are maximum

C. kinetic energy is maximum, potential energy is minimum

D. both kinetic and potential energies are minimum.

Answer : kinetic energy is maximum, potential energy is minimum

Solution :
$$K.E = \frac{1}{2}k\left( {{A^2} - {x^2}} \right);\,U = \frac{1}{2}k{x^2}$$
At the mean position $$x = 0$$
$$\therefore K.E = \frac{1}{2}k{A^2} = $$ Maximum and $$U = 0$$

Releted MCQ Question on
Oscillation and Mechanical Waves >> Simple Harmonic Motion (SHM)

Releted Question 1

Two bodies $$M$$ and $$N$$ of equal masses are suspended from two separate massless springs of spring constants $${k_1}$$ and $${k_2}$$ respectively. If the two bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of vibration of $$M$$ to that of $$N$$ is

A. $$\frac{{{k_1}}}{{{k_2}}}$$

B. $$\sqrt {\frac{{{k_1}}}{{{k_2}}}} $$

C. $$\frac{{{k_2}}}{{{k_1}}}$$

D. $$\sqrt {\frac{{{k_2}}}{{{k_1}}}} $$

Releted Question 2

A particle free to move along the $$x$$-axis has potential energy given by $$U\left( x \right) = k\left[ {1 - \exp \left( { - {x^2}} \right)} \right]$$ for $$ - \infty \leqslant x \leqslant + \infty ,$$ where $$k$$ is a positive constant of appropriate dimensions. Then

A. at points away from the origin, the particle is in unstable equilibrium

B. for any finite nonzero value of $$x,$$ there is a force directed away from the origin

C. if its total mechanical energy is $$\frac{k}{2},$$ it has its minimum kinetic energy at the origin.

D. for small displacements from $$x = 0,$$ the motion is simple harmonic

Releted Question 3

The period of oscillation of a simple pendulum of length $$L$$ suspended from the roof of a vehicle which moves without friction down an inclined plane of inclination $$\alpha ,$$ is given by

A. $$2\pi \sqrt {\frac{L}{{g\cos \alpha }}} $$

B. $$2\pi \sqrt {\frac{L}{{g\sin \alpha }}} $$

C. $$2\pi \sqrt {\frac{L}{g}} $$

D. $$2\pi \sqrt {\frac{L}{{g\tan \alpha }}} $$

Releted Question 4

A particle executes simple harmonic motion between $$x = - A$$ and $$x = + A.$$ The time taken for it to go from 0 to $$\frac{A}{2}$$ is $${T_1}$$ and to go from $$\frac{A}{2}$$ to $$A$$ is $${T_2.}$$ Then

A. $${T_1} < {T_2}$$

B. $${T_1} > {T_2}$$

C. $${T_1} = {T_2}$$

D. $${T_1} = 2{T_2}$$

Practice More Releted MCQ Question on
Simple Harmonic Motion (SHM)

Practice More MCQ Question on Physics Section

Basic Physics Unit and Measurement Kinematics Laws of Motion Friction Uniform Circular Motion Impulse Momentum Work Energy and Power Rotational Motion Gravitation Mechanical Properties of Solids and Fluids

Heat and Thermodynamics Thermodynamics Thermal Expansion Conduction Radiation Calorimetry Kinetic Theory of Gases

Electrostatics and Magnetism Electric Charges Electric Field Electric Potential Capacitors and Dielectrics Magnetic Effect of Current Magnetic Materials Electromagnetic Waves Electric Current Electromagnetic Induction Alternating Current Semiconductors and Electronic Devices

Optics and Wave Ray Optics Wave Optics

Modern Physics Dual Nature of Matter and Radiation Atoms And Nuclei Atoms or Nuclear Fission and Fusion Radioactivity Modern Physics Miscellaneous Semiconductors and Electronic Devices

Oscillation and Mechanical Waves Simple Harmonic Motion (SHM)Waves