Question
For the circuit shown in Figure, which of the following statements is true?
For the circuit shown in Figure, which of the following statements is true?
A.
With $${S_1}$$ closed $${V_1} = 15\,V,{V_2} = 20\,V$$
B.
With $${S_3}$$ closed $${V_1} = {V_2} = 25\,V$$
C.
With $${S_1}$$ and $${S_2}$$ closed, $${V_1} = {V_2} = 0$$
D.
With $${S_1}$$ and $${S_3}$$ closed, $${V_1} = 30\,V,{V_2} = 20\,V$$
Answer :
With $${S_1}$$ and $${S_3}$$ closed, $${V_1} = 30\,V,{V_2} = 20\,V$$
Solution :
With the closing of switch $${S_3}$$ and $${S_1}$$ the negative charge on $${C_2}$$ will attract the positive charge on $${C_2}$$ thereby maintaining the negative charge on $${C_1}.$$ The negative charge on $${C_1}$$ will attract the positive charge on $${C_1}.$$ No transfer of charge will take place. Therefore p.d across $${C_1}$$ and $${C_2}$$ will be $$30 V$$ and $$20 V.$$
With the closing of switch $${S_3}$$ and $${S_1}$$ the negative charge on $${C_2}$$ will attract the positive charge on $${C_2}$$ thereby maintaining the negative charge on $${C_1}.$$ The negative charge on $${C_1}$$ will attract the positive charge on $${C_1}.$$ No transfer of charge will take place. Therefore p.d across $${C_1}$$ and $${C_2}$$ will be $$30 V$$ and $$20 V.$$
