Question

According to Einstein’s photoelectric equation, the plot of the kinetic energy of the emitted photo electrons from a metal Vs the frequency, of the incident radiation gives as straight the whose slope

A. depends both on the intensity of the radiation and the metal used
B. depends on the intensity of the radiation
C. depends on the nature of the metal used
D. is the same for the all metals and independent of the intensity of the radiation  
Answer :   is the same for the all metals and independent of the intensity of the radiation
Solution :
From Equation $$K.E = h\nu - \phi $$
slope of graph of $$K.E.$$  & $$\nu $$ is $$h$$ (Plank's constant) which is same for all metals

Releted MCQ Question on
Modern Physics >> Modern Physics Miscellaneous

Releted Question 1

The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy $$6\,eV$$  fall on it is $$4\,eV.$$  The stopping potential, in volt, is

A. 2
B. 4
C. 6
D. 10
Releted Question 2

Electrons with energy $$80\,keV$$  are incident on the tungsten target of an X-ray tube. $$K$$-shell electrons of tungsten have $$72.5\,keV$$  energy. X-rays emitted by the tube contain only

A. a continuous X-ray spectrum (Bremsstrahlung) with a minimum wavelength of $$0.155\mathop {\text{A}}\limits^ \circ $$
B. a continuous X-ray spectrum (Bremsstrahlung) with all wavelengths
C. the characteristic X-ray spectrum of tungsten
D. a continuous X-ray spectrum (Bremsstrahlung) with a minimum wavelength of $$0.155\mathop {\text{A}}\limits^ \circ $$  and the characteristic X-ray spectrum of tungsten.
Releted Question 3

The intensity of X-rays from a Coolidge tube is plotted against wavelength $$\lambda $$ as shown in the figure. The minimum wavelength found is $${\lambda _C}$$ and the wavelength of the $${K_\alpha }$$ line is $${\lambda _K}.$$  As the accelerating voltage is increased
Modern Physics Miscellaneous mcq question image

A. $${\lambda _K} - {\lambda _C}$$   increases
B. $${\lambda _K} - {\lambda _C}$$   decreases
C. $${\lambda _K}$$ increases
D. $${\lambda _K}$$ decreases
Releted Question 4

The potential difference applied to an X-ray tube is $$5k\,V$$  and the current through it is 3.2$$mA.$$  Then the number of electrons striking the target per second is

A. $$2 \times {10^{16}}$$
B. $$5 \times {10^{6}}$$
C. $$1 \times {10^{17}}$$
D. $$4 \times {10^{15}}$$

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