A transistor-oscillator using a resonant circuit with an inductor $$L$$ (of negligible resistance) and a capacitor $$C$$ in series produce oscillations of frequency $$f.$$ If $$L$$ is doubled and $$C$$ is changed to $$4C,$$ the frequency will be
A.
$$8f$$
B.
$$\frac{f}{{2\sqrt 2 }}$$
C.
$$\frac{f}{2}$$
D.
$$\frac{f}{4}$$
Answer :
$$\frac{f}{{2\sqrt 2 }}$$
Solution :
We know that frequency of electrical oscillation in $$L.C.$$ circuit is
$$\eqalign{
& f = \frac{1}{{2\pi }}\sqrt {\frac{1}{{LC}}} \cr
& {\text{Now,}}\,L = 2L\,\,\& \,\,C = 4C \cr
& f' = \frac{1}{{2\pi }}\sqrt {\frac{1}{{2L \cdot 4C}}} = \frac{1}{{2\pi }}\sqrt {\frac{1}{{LC}}} \times \frac{1}{{2\sqrt 2 }} \Rightarrow f' \cr
& = \frac{1}{{2\sqrt 2 }} \times f \cr} $$
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