A projectile is fired from the surface of the earth with a velocity of $$5\,m{s^{ - 1}}$$ at angle $$\theta $$ with the horizontal. Another projectile fired from another planet with a velocity of $$3\,m{s^{ - 1}}$$ at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in $$m{s^{ - 2}}$$ ) is (given, $$g = 9.8\,m{s^{ - 2}}$$ )
A.
$$3.5$$
B.
$$5.9$$
C.
$$16.3$$
D.
$$110.8$$
Answer :
$$3.5$$
Solution :
The trajectory of a projectile projected at some angle $$\theta $$ with the horizontal direction from ground is given by
$$y = x\tan \theta - \frac{{g{x^2}}}{{2{u^2}{{\cos }^2}\theta }}$$
For equal trajectories for same angle of projection,
$$\eqalign{
& \frac{g}{{{u^2}}} = {\text{constant}} \Rightarrow \frac{{9.8}}{{{5^2}}} = \frac{{g'}}{{{3^2}}} \cr
& g' = \frac{{9.8 \times 9}}{{25}} = 3.5\,m{s^{ - 2}} \cr} $$
Releted MCQ Question on Basic Physics >> Kinematics
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