A polyatomic gas with $$n$$ degrees of freedom has a mean energy per molecule given by
A.
$$\frac{{nkT}}{N}$$
B.
$$\frac{{nkT}}{2N}$$
C.
$$\frac{{nkT}}{2}$$
D.
$$\frac{{3kT}}{2}$$
Answer :
$$\frac{{nkT}}{2}$$
Solution :
According to law of equipartition of energy, the energy per degree of freedom is $$\frac{1}{2}kT.$$ For a polyatomic gas with $$n$$ degrees of freedom, the mean energy per molecule $$ = \frac{1}{2}nkT$$
Releted MCQ Question on Heat and Thermodynamics >> Kinetic Theory of Gases
The average translational kinetic energy of $${O_2}$$ (relative molar mass 32) molecules at a particular temperature is $$0.048\,eV.$$ The translational kinetic energy of $${N_2}$$ (relative molar mass 28) molecules in $$eV$$ at the same temperature is
A vessel contains 1 mole of $${O_2}$$ gas (relative molar mass 32) at a temperature $$T.$$ The pressure of the gas is $$P.$$ An identical vessel containing one mole of $$He$$ gas (relative molar mass 4) at a temperature $$2\,T$$ has a pressure of