Question
A plane electromagnetic wave of frequency $$50\,MHz$$ travels in free space along the positive $$x$$-direction. At a particular point in space and time, $$\vec E = 6.3\hat j\,V/m.$$ The corresponding magnetic field $${\vec B},$$ at that point will be:
A.
$$18.9 \times {10^{ - 8}}$$
B.
$$2.1 \times {10^{ - 8}}$$
C.
$$6.3 \times {10^{ - 8}}$$
D.
$$18.9 \times {10^8}$$
Answer :
$$2.1 \times {10^{ - 8}}$$
Solution :
As we know,
$$\left| B \right| = \frac{{\left| E \right|}}{C} = \frac{{6.3}}{{3 \times {{10}^8}}} = 2.1 \times {10^{ - 8}}T$$
As $$\vec V \bot \vec E \bot \vec B$$ therefore direction of is in z direction
$$\vec B = 2.1 \times {10^{ - 8}}\hat kT$$