A magnetic field $$\overrightarrow B = {B_0}\hat j,$$ exists in the region $$a < x < 2a,$$ and $$\overrightarrow B = - {B_0}\hat j,$$ in the region $$2a < x < 3a,$$ where $${B_0}$$ is a positive constant. A positive point charge moving with a velocity $$v = {v_0}\hat i,$$ where $${v_0}$$ is a positive constant, enters the magnetic field at $$x = a.$$ The trajectory of the charge in this region can be like
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B.
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D.
Answer :
Solution :
Use the vector form of $$B$$ and $$v$$ in the formulae $$\overrightarrow F = q\left( {\overrightarrow v \times \overrightarrow B } \right)$$ to get the instantaneous direction of force at $$x = a$$ and $$x = 2a.$$
Releted MCQ Question on Electrostatics and Magnetism >> Magnetic Effect of Current
Releted Question 1
A conducting circular loop of radius $$r$$ carries a constant current $$i.$$ It is placed in a uniform magnetic field $${{\vec B}_0}$$ such that $${{\vec B}_0}$$ is perpendicular to the plane of the loop. The magnetic force acting on the loop is
A battery is connected between two points $$A$$ and $$B$$ on the circumference of a uniform conducting ring of radius $$r$$ and resistance $$R.$$ One of the arcs $$AB$$ of the ring subtends an angle $$\theta $$ at the centre. The value of the magnetic induction at the centre due to the current in the ring is
A.
proportional to $$2\left( {{{180}^ \circ } - \theta } \right)$$
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