Question

Which one of the statements about $$HO{H_2}CCH\left( {OH} \right)CHO$$      is not correct? It

A. is an isomer of 1, 3-dihydroxypropanone
B. contains a tertiary alcoholic group  
C. has the same empirical formula as glucose
D. can show optical isomerism
Answer :   contains a tertiary alcoholic group
Solution :
\[\underset{\begin{smallmatrix} |\,\,\,\, \\ \,\,\,\,\,\,C{{H}_{2}}OH \end{smallmatrix}}{\overset{\begin{smallmatrix} \,\,\,CHO \\ |\,\,\,\, \end{smallmatrix}}{\mathop{H-C-OH}}}\,\]
It contains one primary and one secondary alcoholic group thus, option (B) is incorrect.

Releted MCQ Question on
Organic Chemistry >> Aldehyde and Ketone

Releted Question 1

The reagent with which both acetaldehyde and acetone react easily is

A. Fehling’s reagent
B. Grignard reagent
C. Schiff’s reagent
D. Tollen’s reagent
Releted Question 2

The Cannizzaro reaction is not given by

A. trimethylacetaldehye
B. acetaldehyde
C. benzaldehyde
D. formaldehyde
Releted Question 3

The compound that will not give iodoform on treatment with alkali and iodine is :

A. acetone
B. ethanol
C. diethyl ketone
D. isopropyl alcohol
Releted Question 4

Polarisation of electrons in acrolein may be written as

A. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = CH - \mathop {CH}\limits^{{\delta ^ + }} = O$$
B. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = CH - CH = \mathop O\limits^{{\delta ^ + }} $$
C. $$\mathop {C{H_2}}\limits^{{\delta ^ - }} = \mathop {CH}\limits^{{\delta ^ + }} - CH = O$$
D. $$\mathop {C{H_2}}\limits^{{\delta ^ + }} = CH - CH = \mathop O\limits^{{\delta ^ - }} $$

Practice More Releted MCQ Question on
Aldehyde and Ketone


Practice More MCQ Question on Chemistry Section