Question

Which one of the following is an inner orbital complex as well as diamagnetic in behaviour ?
$$\left( {{\text{At}}{\text{. no}}{\text{. of}}\,\,Zn = 30,Cr = 24,Co = 27,Ni = 28} \right)$$

A. $${\left[ {Zn{{\left( {N{H_3}} \right)}_6}} \right]^{2 + }}$$
B. $${\left[ {Cr{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }}$$
C. $${\left[ {Co{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }}$$  
D. $${\left[ {Ni{{\left( {N{H_3}} \right)}_6}} \right]^{2 + }}$$
Answer :   $${\left[ {Co{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }}$$
Solution :
In $${\left[ {Co{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }},$$   oxidation state of $$Co = + 3$$   and its coordination number is six.
$$\eqalign{ & _{27}Co = 1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^7},4{s^2} \cr & C{o^{3 + }} = 1{s^2},2{s^2}2{p^6},3{s^2}3{p^6}3{d^6} \cr} $$
Co-ordination Compounds mcq solution image
$${\left[ {Co{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }}$$   is an inner orbital complex as well as diamagnetic in behaviour ( due to absence of unpaired electrons ).
$${\left[ {Zn{{\left( {N{H_3}} \right)}_6}} \right]^{2 + }} \to s{p^3}{d^2}$$     hybridisation ( outer orbital complex and diamagnetic in nature ).
$${\left[ {Cr{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }} \to {d^2}s{p^3}$$     hybridisation ( inner orbital complex and paramagnetic in nature ).

Releted MCQ Question on
Inorganic Chemistry >> Co - ordination Compounds

Releted Question 1

Amongst $$Ni{\left( {CO} \right)_4},{\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}{\text{and}}\,NiCl_4^{2 - }$$

A. $$Ni{\left( {CO} \right)_4}\,{\text{and}}\,NiCl_4^{2 - }$$     are diamagnetic and $${\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$$   is paramagnetic
B. $$NiCl_4^{2 - }\,{\text{and}}\,{\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$$     are diamagnetic and $$Ni{\left( {CO} \right)_4}$$   is paramagnetic
C. $$Ni{\left( {CO} \right)_4}\,{\text{and}}\,{\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$$     are diamagnetic and $$NiCl_4^{2 - }$$  is paramagnetic
D. $$Ni{\left( {CO} \right)_4}$$  is diamagnetic and $$NiCl_4^{2 - }\,{\text{and}}\,{\left[ {Ni{{\left( {CN} \right)}_4}} \right]^{2 - }}$$     are paramagnetic
Releted Question 2

The geometry of $$Ni{\left( {CO} \right)_4}\,{\text{and}}\,Ni{\left( {PP{h_3}} \right)_2}C{l_2}\,{\text{are}}$$

A. both square planar
B. tetrahedral and square planar, respectively
C. both tetrahedral
D. square planar and tetrahedral, respectively
Releted Question 3

The complex ion which has no $$'d'$$ electron in the central metal atom is

A. $${\left[ {Mn{O_4}} \right]^ - }$$
B. $${\left[ {Co{{\left( {N{H_3}} \right)}_6}} \right]^{3 + }}$$
C. $${\left[ {Fe{{\left( {CN} \right)}_6}} \right]^{3 - }}$$
D. $${\left[ {Cr{{\left( {{H_2}O} \right)}_6}} \right]^{3 + }}$$
Releted Question 4

In the process of extraction of gold,
Roasted gold ore $$ + C{N^ - } + {H_2}O\mathop \to \limits^{{O_2}} \left[ X \right] + O{H^ - }$$
$$\left[ X \right] + Zn \to \left[ Y \right] + Au$$
Identify the complexes $$\left[ X \right]\,\,{\text{and}}\,\,\left[ Y \right]$$

A. $$X = {\left[ {Au{{\left( {CN} \right)}_2}} \right]^ - },Y = {\left[ {Zn{{\left( {CN} \right)}_4}} \right]^{2 - }}$$
B. $$X = {\left[ {Au{{\left( {CN} \right)}_4}} \right]^{3 - }},Y = {\left[ {Zn{{\left( {CN} \right)}_4}} \right]^{2 - }}$$
C. $$X = {\left[ {Au{{\left( {CN} \right)}_2}} \right]^ - },Y = {\left[ {Zn{{\left( {CN} \right)}_6}} \right]^{4 - }}$$
D. $$X = {\left[ {Au{{\left( {CN} \right)}_4}} \right]^ - },Y = {\left[ {Zn{{\left( {CN} \right)}_4}} \right]^{2 - }}$$

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Co - ordination Compounds


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