Question
Which one of the following does not have a pyramidal shape ?
A.
$${\left( {C{H_3}} \right)_3}N$$
B.
$${\left( {Si{H_3}} \right)_3}N$$
C.
$$P{\left( {C{H_3}} \right)_3}$$
D.
$$P{\left( {Si{H_3}} \right)_3}$$
Answer :
$${\left( {Si{H_3}} \right)_3}N$$
Solution :
In case of $$N{\left( {Si{H_3}} \right)_3},N$$ atom is $$s{p^2}$$ hybridised, the lone pair is present in $$2p$$ orbital and it is transferred to empty $$d$$ orbital of $$Si$$ forming $$d\pi - p\pi $$ bond. Hence nitrogen with $$s{p^2}$$ hybridization has trigonal planar shape.