Question
Which one of the following compounds has the smallest bond angle in its molecule ?
A.
$$O{H_2}\,$$
B.
$$S{H_2}$$
C.
$$N{H_3}\,$$
D.
$$S{O_2}$$
Answer :
$$S{H_2}$$
Solution :
In $${H_2}S,$$ due to low electronegativity of sulphur the $$L.P.\,{\text{ - }}\,L.P.$$ repulsion is more than $$B.P.\,{\text{ - }}\,B.P.$$ repulsion and hence the bond angle is minimum.
\[\begin{matrix}
{} \\
\text{Bond angle} \\
\end{matrix}\,\,\,\begin{matrix}
S{{O}_{2}} \\
{{119.5}^{\circ }} \\
\end{matrix}\,\,\begin{matrix}
{{H}_{2}}O \\
{{104.5}^{\circ }} \\
\end{matrix}\,\,\begin{matrix}
{{H}_{2}}S \\
{{92.5}^{\circ }} \\
\end{matrix}\,\,\begin{matrix}
N{{H}_{3}} \\
{{106.5}^{\circ }} \\
\end{matrix}\]