Question
Which of the following will have maximum total kinetic energy at temperature $$300K$$ ?
A.
$$1\,kg\,{H_2}$$
B.
$$1\,kg\,He$$
C.
$$\frac{1}{2}kg\,{H_2} + \frac{1}{2}kg\,He$$
D.
$$\frac{1}{2}kg\,{H_2} + \frac{3}{4}kg\,He$$
Answer :
$$1\,kg\,{H_2}$$
Solution :
Total Kinetic Energy $$ = U = \frac{f}{2}nRT$$
In case of $${H_2}$$ degree of freedom is greatest and number of moles $$n$$ is highest.
So this is the case of maximum kinetic energy.