Question
Which of the following reactions will have the value of enthalpy of neutralisation as $$ - 57.1\,kJ\,mo{l^{ - 1}}?$$
A.
$$C{H_3}COOH + NaOH \to C{H_3}COONa + {H_2}O$$
B.
$$HCl + NaOH \to NaCl + {H_2}O$$
C.
$$HCl + N{H_4}OH \to N{H_4}Cl + {H_2}O$$
D.
$$HCOOH + NaOH \to HCOONa + {H_2}O$$
Answer :
$$HCl + NaOH \to NaCl + {H_2}O$$
Solution :
Enthalpy of neutralisation is $$ - 57.1\,kJ\,mo{l^{ - 1}}$$ for a strong acid and a strong base.