Which of the following is more basic than aniline?
A.
Diphenylamine
B.
Triphenylamine
C.
$$p$$ - nitroaniline
D.
Benzylamine
Answer :
Benzylamine
Solution :
Benzylamine, $${C_6}{H_5}C{H_2} - \ddot N{H_2}$$ is more basic than aniline because benzyl group $$\left( {{C_6}{H_5}C{H_2} - } \right)$$ is electron donating group due to $$ + I$$ - effect So, it is able to increase the electron density of $$N$$ of $$ - N{H_2}$$ group. Thus, due to higher electron density, rate of donation of free pair of electron is increased, i.e. basic character is higher. Phenyl and nitro group are electron withdrawing groups, so they decreases the electron density on $$N$$ of \[-\ddot{N}{{H}_{2}}\] group. Hence, they are less basic than aniline.