Question

Which of the following is correct representation of a given molecular equation in ionic form?
$${K_2}C{r_2}{O_7} + 7{H_2}S{O_4} + 6FeS{O_4} \to $$       $$3F{e_2}{\left( {S{O_4}} \right)_3} + C{r_2}{\left( {S{O_4}} \right)_3} + {K_2}S{O_4}$$       $$ + 7{H_2}O$$

A. $$C{r_2}O_7^{2 - } + 14{H^ + } + 6F{e^{2 + }} \to $$       $$6F{e^{3 + }} + 2C{r^{3 + }} + 7{H_2}O$$  
B. $$2{K^ + } + C{r_2}O_7^{2 - } + 7SO_4^{2 - } + 6F{e^{2 + }}$$       $$ \to 3F{e^{3 + }} + SO_4^{2 - } + C{r^{3 + }} + {K^ + }$$       $$ + 7{H_2}O$$
C. $$C{r_2}O_7^{2 - } + 2{K^ + } + 7{H^ + } + 6F{e^{2 + }} \to $$       $$6F{e^{3 + }} + 6C{r^{3 + }} + {K^ + }$$
D. $$C{r_2}O_7^{2 - } + 7{H^ + } + 6F{e^{2 + }} \to $$       $$3F{e^{2 + }} + 2C{r^{3 + }} + 2{K^ + } + 7{H_2}O$$
Answer :   $$C{r_2}O_7^{2 - } + 14{H^ + } + 6F{e^{2 + }} \to $$       $$6F{e^{3 + }} + 2C{r^{3 + }} + 7{H_2}O$$
Solution :
$${K_2}C{r_2}{O_7} + 7{H_2}S{O_4} + 6FeS{O_4} \to $$       $$3F{e_2}{\left( {S{O_4}} \right)_3} + C{r_2}{\left( {S{O_4}} \right)_3} + 7{H_2}O$$       $$ + {K_2}S{O_4}$$
$${\text{In ionic form}}\,:$$
$$2{K^ + } + C{r_2}O_7^{2 - } + 14{H^ + } + 7SO_4^{2 - }$$       $$ + 6F{e^{2 + }} + 6SO_4^{2 - } \to 6F{e^{3 + }} + 9SO_4^{2 - }$$       $$ + 2C{r^{3 + }} + 3SO_4^{2 - } + 2{K^ + } + SO_4^{2 - }$$       $$ + 7{H_2}O$$
$${\text{Eliminating the common species :}}$$
$$C{r_2}O_7^{2 - } + 14{H^ + } + 6F{e^{2 + }} \to $$       $$6F{e^{3 + }} + 2C{r^{3 + }} + 7{H_2}O$$

Releted MCQ Question on
Physical Chemistry >> Redox Reaction

Releted Question 1

Which of the following represents a redox reaction?

A. $$NaOH + HCl \to NaCl + {H_2}O$$
B. $$BaC{l_2} + {H_2}S{O_4} \to BaS{O_4} + 2HCl$$
C. $$CuS{O_4} + 2{H_2}O \to Cu{\left( {OH} \right)_2} + {H_2}S{O_4}$$
D. $$Zn + 2HCl \to ZnC{l_2} + {H_2}$$
Releted Question 2

Which reaction involves neither oxidation nor reduction?

A. $$CrO_4^{2 - } \to C{r_2}O_7^{2 - }$$
B. $$Cr \to CrC{l_3}$$
C. $$Na \to N{a^ + }$$
D. $$2{S_2}O_3^{2 - } \to {S_4}O_6^{2 - }$$
Releted Question 3

$$Zn$$  gives $${H_2}$$  gas with $${H_2}S{O_4}$$  and $$HCl$$  but not with $$HN{O_3}$$  because

A. Zn acts as an oxidising agent when it reacts with $$HN{O_3}$$
B. $$HN{O_3}$$  is weaker acid than $${H_2}S{O_4}$$  and $$HCl$$
C. In electrochemical series, $$Zn$$  is above hydrogen
D. $$NO_3^ - $$  is reduced in preference to hydronium $$ion$$
Releted Question 4

A compound of $$Xe$$  and $$F$$  is found to have $$53.5\% $$  of $$Xe.$$  What is oxidation number of $$Xe$$  in this compound ?

A. $$-4$$
B. $$0$$
C. $$+4$$
D. $$+6$$

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Redox Reaction


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