Which of the following ions has the maximum magnetic moment?
A.
$$M{n^{ + 2}}$$
B.
$$F{e^{ + 2}}$$
C.
$$T{i^{ + 2}}$$
D.
$$C{r^{ + 2}}$$
Answer :
$$M{n^{ + 2}}$$
Solution :
$$\eqalign{
& M{n^{ + + }} - 5\,\,{\text{unpaired}}\,{\text{electrons}} \cr
& {\text{F}}{{\text{e}}^{ + + }} - 4\,{\text{unpaired}}\,{\text{electrons}} \cr
& T{i^{ + + }} - 2\,{\text{unpaired}}\,{\text{electrons}} \cr
& C{r^{ + + }} - 4\,{\text{unpaired}}\,{\text{electrons}} \cr} $$
hence maximum no. of unpaired electron is present in $$M{n^{ + + }}.$$
NOTE : Magnetic moment $$ \propto $$ number of unpaired
electrons
Releted MCQ Question on Inorganic Chemistry >> D and F Block Elements
Releted Question 1
When same amount of zinc is treated separately with excess of sulphuric acid and excess of sodium hydroxide, the ratio of volume of hydrogen evolved is