When kept open in air, the crystals of washing soda lose 9 molecules of water to form a monohydrate. \[N{{a}_{2}}C{{O}_{3}}\cdot 10{{H}_{2}}O\xrightarrow[\text{to}\,\,\text{air}]{\text{exposed}}\] $$N{a_2}C{O_3} \cdot {H_2}O + 9{H_2}O$$ This process is called

Question

When kept open in air, the crystals of washing soda lose 9 molecules of water to form a monohydrate. \[N{{a}_{2}}C{{O}_{3}}\cdot 10{{H}_{2}}O\xrightarrow[\text{to}\,\,\text{air}]{\text{exposed}}\] $$N{a_2}C{O_3} \cdot {H_2}O + 9{H_2}O$$
This process is called

A. efflorescence

B. deliquescence

C. dehydration

D. hydration

Answer : efflorescence

Releted MCQ Question on
Inorganic Chemistry >> S - Block Elements

Releted Question 1

A substance absorbs $$C{O_2}$$ and voilently reacts with water. The substance is

A. $$CaC{O_3}$$

B. $$CaO$$

C. $${H_2}S{O_4}$$

D. $$ZnO$$

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Releted Question 2

Calcium is obtained by

A. electrolysis of molten $$CaC{l_2}.$$

B. electrolysis of solution of $$CaC{l_2}$$ in water.

C. Reduction of $$CaC{l_2}$$ with carbon.

D. roasting of limestone.

View Answer

Releted Question 3

A solution of sodium metal in liquid ammonia is strongly reducing due to the presence of

A. sodium atoms

B. sodium hydride

C. sodium amide

D. solvated electrons

View Answer

Releted Question 4

The hydration energy of $$M{g^{ + + }}$$ is larger than that of :

A. $$A{l^{3 + }}$$

B. $$N{a^ + }$$

C. $$B{e^{ + + }}$$

D. $$M{g^{3 + }}$$

View Answer

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When kept open in air, the crystals of washing soda lose 9 molecules of water to form a monohydrate. \[N{{a}_{2}}C{{O}_{3}}\cdot 10{{H}_{2}}O\xrightarrow[\text{to}\,\,\text{air}]{\text{exposed}}\] $$N{a_2}C{O_3} \cdot {H_2}O + 9{H_2}O$$ This process is called

Releted MCQ Question on Inorganic Chemistry >> S - Block Elements

A substance absorbs $$C{O_2}$$ and voilently reacts with water. The substance is

Calcium is obtained by

A solution of sodium metal in liquid ammonia is strongly reducing due to the presence of

The hydration energy of $$M{g^{ + + }}$$ is larger than that of :

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When kept open in air, the crystals of washing soda lose 9 molecules of water to form a monohydrate. \[N{{a}_{2}}C{{O}_{3}}\cdot 10{{H}_{2}}O\xrightarrow[\text{to}\,\,\text{air}]{\text{exposed}}\] $$N{a_2}C{O_3} \cdot {H_2}O + 9{H_2}O$$
This process is called

Releted MCQ Question on
Inorganic Chemistry >> S - Block Elements

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S - Block Elements