When burnt in air, $$14.0\,g$$  mixture of carbon and sulphur gives a mixture of $$C{O_2}$$  and $$S{O_2}$$  in the volume ratio of 2 : 1, volume being measured at the same conditions of temperature and pressure moles of carbon in the mixture is

Solution :
Let weight of $$C$$  be $$x\,g,$$  then $$S$$  will be $$\left( {14 - x} \right)g$$
$$\eqalign{ & \frac{{\frac{x}{{12}}}}{{\frac{{\left( {14 - x} \right)}}{{32}}}} = \frac{2}{1} \cr & \therefore \,\,x = 6\,g\,;\,{\text{Moles of}}\,C = \frac{6}{{12}} = 0.5 \cr} $$