Question
When a system is taken from state $$i$$ to state $$f$$ along the path iaf, it is found that $$Q = 50\,cal.$$ and $$W = 20\,cal.$$ Along the path
ibf $$Q = 36\,cal.$$ $$W$$ along the path ibf is
When a system is taken from state $$i$$ to state $$f$$ along the path iaf, it is found that $$Q = 50\,cal.$$ and $$W = 20\,cal.$$ Along the path
ibf $$Q = 36\,cal.$$ $$W$$ along the path ibf is
A.
$$14\,cal$$
B.
$$6\,cal$$
C.
$$16\,cal$$
D.
$$66\,cal$$
Answer :
$$6\,cal$$
Solution :
For path iaf,
$$\eqalign{ & \Delta U = Q - W \cr & = 50 - 20 \cr & = 30\,\,{{cal}}{\text{.}} \cr} $$
For path ibf,
$$\eqalign{ & W = Q - \Delta U \cr & = 36 - 30 \cr & = 6\,\,{{cal}}{\text{.}} \cr} $$
For path iaf,
$$\eqalign{ & \Delta U = Q - W \cr & = 50 - 20 \cr & = 30\,\,{{cal}}{\text{.}} \cr} $$
For path ibf,
$$\eqalign{ & W = Q - \Delta U \cr & = 36 - 30 \cr & = 6\,\,{{cal}}{\text{.}} \cr} $$
