Two numbers are selected randomly from the set $$S = \left\{ {1,2,3,4,5,6} \right\}$$ without replacement one by one. The probability that minimum of the two numbers is less than 4 is
A.
$$\frac{1}{{15}}$$
B.
$$\frac{14}{{15}}$$
C.
$$\frac{1}{{5}}$$
D.
$$\frac{4}{{5}}$$
Answer :
$$\frac{4}{{5}}$$
Solution :
The minimum of two numbers will be less than 4 if at least one of the numbers is less than 4.
∴ $$P$$ (at least one no. is < 4),
= $$1 - P$$ (both the no’s are $$ \geqslant $$ 4)
$$\eqalign{
& = 1 - \frac{3}{6} \times \frac{2}{5} \cr
& = 1 - \frac{6}{{30}} \cr
& = 1 - \frac{1}{5} \cr
& = \frac{4}{5} \cr} $$
Releted MCQ Question on Statistics and Probability >> Probability
Releted Question 1
Two fair dice are tossed. Let $$x$$ be the event that the first die shows an even number and $$y$$ be the event that the second die shows an odd number. The two events $$x$$ and $$y$$ are:
Two events $$A$$ and $$B$$ have probabilities 0.25 and 0.50 respectively. The probability that both $$A$$ and $$B$$ occur simultaneously is 0.14. Then the probability that neither $$A$$ nor $$B$$ occurs is
The probability that an event $$A$$ happens in one trial of an experiment is 0.4. Three independent trials of the experiment are performed. The probability that the event $$A$$ happens at least once is
If $$A$$ and $$B$$ are two events such that $$P(A) > 0,$$ and $$P\left( B \right) \ne 1,$$ then $$P\left( {\frac{{\overline A }}{{\overline B }}} \right)$$ is equal to
(Here $$\overline A$$ and $$\overline B$$ are complements of $$A$$ and $$B$$ respectively).
A.
$$1 - P\left( {\frac{A}{B}} \right)$$
B.
$$1 - P\left( {\frac{{\overline A }}{B}} \right)$$
C.
$$\frac{{1 - P\left( {A \cup B} \right)}}{{P\left( {\overline B } \right)}}$$
D.
$$\frac{{P\left( {\overline A } \right)}}{{P\left( {\overline B } \right)}}$$