Total number of words that can be formed using all letters of the word $$FAILURE$$ which neither begin with $$F$$ nor end with $$E$$ is equal to
A.
3720
B.
5040
C.
3600
D.
3480
Answer :
3720
Solution :
Total number of words $$= 7!$$
Out of which $$6!$$ start with $$F$$ and $$6!$$ and with $$E,$$ while $$5!$$ start with $$F$$ and end with $$E.$$
Releted MCQ Question on Algebra >> Permutation and Combination
Releted Question 1
$$^n{C_{r - 1}} = 36,{\,^n}{C_r} = 84$$ and $$^n{C_{r + 1}} = 126,$$ then $$r$$ is:
Ten different letters of an alphabet are given. Words with five letters are formed from these given letters. Then the number of words which have at least one letter repeated are
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