Question

The $$rms$$  value of the electric field of the light coming from the Sun is $$720\,N/C.$$  The average total energy density of the electromagnetic wave is

A. $$4.58 \times {10^{ - 6}}J/{m^3}$$  
B. $$6.37 \times {10^{ - 9}}J/{m^3}$$
C. $$81.35 \times {10^{ - 12}}J/{m^3}$$
D. $$3.3 \times {10^{ - 3}}J/{m^3}$$
Answer :   $$4.58 \times {10^{ - 6}}J/{m^3}$$
Solution :
$${E_{rms}} = 720$$
The average total energy density
$$\eqalign{ & \frac{1}{2}{ \in _0}E_0^2 = \frac{1}{2}{ \in _0}{\left[ {\sqrt 2 {E_{rms}}} \right]^2} = { \in _0}E_{rms}^2 \cr & = 8.85 \times {10^{ - 12}} \times {\left( {720} \right)^2} = 4.58 \times {10^{ - 6}}J/{m^3} \cr} $$

Releted MCQ Question on
Modern Physics >> Modern Physics Miscellaneous

Releted Question 1

The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy $$6\,eV$$  fall on it is $$4\,eV.$$  The stopping potential, in volt, is

A. 2
B. 4
C. 6
D. 10
Releted Question 2

Electrons with energy $$80\,keV$$  are incident on the tungsten target of an X-ray tube. $$K$$-shell electrons of tungsten have $$72.5\,keV$$  energy. X-rays emitted by the tube contain only

A. a continuous X-ray spectrum (Bremsstrahlung) with a minimum wavelength of $$0.155\mathop {\text{A}}\limits^ \circ $$
B. a continuous X-ray spectrum (Bremsstrahlung) with all wavelengths
C. the characteristic X-ray spectrum of tungsten
D. a continuous X-ray spectrum (Bremsstrahlung) with a minimum wavelength of $$0.155\mathop {\text{A}}\limits^ \circ $$  and the characteristic X-ray spectrum of tungsten.
Releted Question 3

The intensity of X-rays from a Coolidge tube is plotted against wavelength $$\lambda $$ as shown in the figure. The minimum wavelength found is $${\lambda _C}$$ and the wavelength of the $${K_\alpha }$$ line is $${\lambda _K}.$$  As the accelerating voltage is increased
Modern Physics Miscellaneous mcq question image

A. $${\lambda _K} - {\lambda _C}$$   increases
B. $${\lambda _K} - {\lambda _C}$$   decreases
C. $${\lambda _K}$$ increases
D. $${\lambda _K}$$ decreases
Releted Question 4

The potential difference applied to an X-ray tube is $$5k\,V$$  and the current through it is 3.2$$mA.$$  Then the number of electrons striking the target per second is

A. $$2 \times {10^{16}}$$
B. $$5 \times {10^{6}}$$
C. $$1 \times {10^{17}}$$
D. $$4 \times {10^{15}}$$

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