The work done in an adiabatic change in a particular gas depends only upon
A.
change in volume
B.
change in temperature
C.
change in pressure
D.
None of these
Answer :
change in temperature
Solution :
In adiabatic process, no heat is taken or given by the system i.e.,
$$\Delta Q = 0 \Rightarrow \Delta U = - \Delta W$$
If $$\Delta W$$ is negative (work done on system), then $$\Delta U$$ increases & temperature increases and vice-versa. So work done in adiabatic change in particular gas (ideal gas) depends on change in temperature.
Releted MCQ Question on Heat and Thermodynamics >> Thermodynamics
Releted Question 1
An ideal monatomic gas is taken round the cycle $$ABCDA$$ as shown in the $$P - V$$ diagram (see Fig.). The work done during the cycle is
If one mole of a monatomic gas $$\left( {\gamma = \frac{5}{3}} \right)$$ is mixed with one mole of a diatomic gas $$\left( {\gamma = \frac{7}{5}} \right)$$ the value of $$\gamma $$ for mixture is
A closed compartment containing gas is moving with some acceleration in horizontal direction. Neglect effect of gravity. Then the pressure in the compartment is
A gas mixture consists of 2 moles of oxygen and 4 moles of argon at temperature $$T.$$ Neglecting all vibrational modes, the total internal energy of the system is