Question

The value of $$\tan \left\{ {2{{\tan }^{ - 1}}\frac{1}{5} - \frac{\pi }{4}} \right\}$$    is

A. $$0$$
B. $$1$$
C. $$\frac{7}{{17}}$$
D. None of these  
Answer :   None of these
Solution :
$$2{\tan ^{ - 1}}\frac{1}{5} = {\tan ^{ - 1}}\frac{{2 \cdot \frac{1}{5}}}{{1 - {{\left( {\frac{1}{5}} \right)}^2}}} = {\tan ^{ - 1}}\frac{5}{{12}}$$
∴ the value $$ = \frac{{\tan \left( {{{\tan }^{ - 1}}\frac{5}{{12}}} \right) - \tan \frac{\pi }{4}}}{{1 + \tan \left( {{{\tan }^{ - 1}}\frac{5}{{12}}} \right) \cdot \tan \frac{\pi }{4}}} = \frac{{\frac{5}{{12}} - 1}}{{1 + \frac{5}{{12}} \cdot 1}}.$$

Releted MCQ Question on
Trigonometry >> Inverse Trigonometry Function

Releted Question 1

The value of $$\tan \left[ {{{\cos }^{ - 1}}\left( {\frac{4}{5}} \right) + {{\tan }^{ - 1}}\left( {\frac{2}{3}} \right)} \right]$$      is

A. $$\frac{6}{{17}}$$
B. $$\frac{7}{{16}}$$
C. $$\frac{16}{{7}}$$
D. none
Releted Question 2

If we consider only the principle values of the inverse trigonometric functions then the value of $$\tan \left( {{{\cos }^{ - 1}}\frac{1}{{5\sqrt 2 }} - {{\sin }^{ - 1}}\frac{4}{{\sqrt {17} }}} \right)$$      is

A. $$\frac{{\sqrt {29} }}{3}$$
B. $$\frac{{29}}{3}$$
C. $$\frac{{\sqrt {3}}}{29}$$
D. $$\frac{{3}}{29}$$
Releted Question 3

The number of real solutions of $${\tan ^{ - 1}}\sqrt {x\left( {x + 1} \right)} + {\sin ^{ - 1}}\sqrt {{x^2} + x + 1} = \frac{\pi }{2}$$         is

A. zero
B. one
C. two
D. infinite
Releted Question 4

If $${\sin ^{ - 1}}\left( {x - \frac{{{x^2}}}{2} + \frac{{{x^3}}}{4} - .....} \right) + {\cos ^{ - 1}}\left( {{x^2} - \frac{{{x^4}}}{2} + \frac{{{x^6}}}{4} - .....} \right) = \frac{\pi }{2}$$             for $$0 < \left| x \right| < \sqrt 2 ,$$   then $$x$$ equals

A. $$ \frac{1}{2}$$
B. 1
C. $$ - \frac{1}{2}$$
D. $$- 1$$

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Inverse Trigonometry Function


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