The value of Henry's law constant for some gases at $$293\,K$$ is given below. Arrange the gases in the increasing order of their solubility.
$$\eqalign{
& He:144.97\,kbar,{H_2}:69.16\,kbar, \cr
& {N_2}:76.48\,kbar,{O_2}:34.86\,kbar \cr} $$
A.
$$He < {N_2} < {H_2} < {O_2}$$
B.
$${O_2} < {H_2} < {N_2} < He$$
C.
$${H_2} < {N_2} < {O_2} < He$$
D.
$$He < {O_2} < {N_2} < {H_2}$$
Answer :
$$He < {N_2} < {H_2} < {O_2}$$
Solution :
Higher the value of $${K_H},$$ lower is the solubility of gas in the liquid.
Releted MCQ Question on Physical Chemistry >> Solutions
Releted Question 1
An azeotropic solution of two liquids has boiling point lower than either of them when it