Question
The value of $${C_p} - {C_v}$$ is $$1.00R$$ for a gas sample in state $$A$$ and is $$1.06R$$ in state $$B.$$ Let $${p_A},{p_B}$$ denote the pressure and $${T_A},{T_B}$$ denote the temperature of the states $$A$$ and $$B$$ respectively. Then most likely
A.
$${p_A} < {p_B}\,{\text{and}}\,{T_A} > {T_B}$$
B.
$${p_A} > {p_B}\,{\text{and}}\,{T_A} < {T_B}$$
C.
$${p_A} = {p_B}\,{\text{and}}\,{T_A} < {T_B}$$
D.
$${p_A} > {p_B}\,{\text{and}}\,{T_A} = {T_B}$$
Answer :
$${p_A} < {p_B}\,{\text{and}}\,{T_A} > {T_B}$$
Solution :
For ideal gas $${C_p} - {C_v} = R$$
If $${C_p} - {C_v} = 1.06\,R,$$
then gas will be real gas. Thus pressure is high and temperature is low for real gas.