Question

The surface of a metal is illuminted with the light of $$400\,nm.$$  The kinetic energy of the ejected photo electrons was found to be $$1.68\,eV.$$  The work function of the metal is :
$$\left( {hc = 1240\,eV.nm} \right)$$

A. $$1.41\,eV$$  
B. $$1.51\,eV$$
C. $$1.68\,eV$$
D. $$3.09\,eV$$
Answer :   $$1.41\,eV$$
Solution :
$$\eqalign{ & \lambda = 400nm,hc = 1240\,eVnm,K.E. = 1.68\,eV \cr & {\text{We}}\,{\text{know}}\,{\text{that}}\,\frac{{hc}}{\lambda } - W = K.E \Rightarrow W = \frac{{hc}}{\lambda } - K.E \cr & \Rightarrow W = \frac{{1240}}{{400}} - 1.68 = 3.1 - 1.68 = 1.42\,eV \approx 1.41\,eV \cr} $$

Releted MCQ Question on
Modern Physics >> Modern Physics Miscellaneous

Releted Question 1

The maximum kinetic energy of photoelectrons emitted from a surface when photons of energy $$6\,eV$$  fall on it is $$4\,eV.$$  The stopping potential, in volt, is

A. 2
B. 4
C. 6
D. 10
Releted Question 2

Electrons with energy $$80\,keV$$  are incident on the tungsten target of an X-ray tube. $$K$$-shell electrons of tungsten have $$72.5\,keV$$  energy. X-rays emitted by the tube contain only

A. a continuous X-ray spectrum (Bremsstrahlung) with a minimum wavelength of $$0.155\mathop {\text{A}}\limits^ \circ $$
B. a continuous X-ray spectrum (Bremsstrahlung) with all wavelengths
C. the characteristic X-ray spectrum of tungsten
D. a continuous X-ray spectrum (Bremsstrahlung) with a minimum wavelength of $$0.155\mathop {\text{A}}\limits^ \circ $$  and the characteristic X-ray spectrum of tungsten.
Releted Question 3

The intensity of X-rays from a Coolidge tube is plotted against wavelength $$\lambda $$ as shown in the figure. The minimum wavelength found is $${\lambda _C}$$ and the wavelength of the $${K_\alpha }$$ line is $${\lambda _K}.$$  As the accelerating voltage is increased
Modern Physics Miscellaneous mcq question image

A. $${\lambda _K} - {\lambda _C}$$   increases
B. $${\lambda _K} - {\lambda _C}$$   decreases
C. $${\lambda _K}$$ increases
D. $${\lambda _K}$$ decreases
Releted Question 4

The potential difference applied to an X-ray tube is $$5k\,V$$  and the current through it is 3.2$$mA.$$  Then the number of electrons striking the target per second is

A. $$2 \times {10^{16}}$$
B. $$5 \times {10^{6}}$$
C. $$1 \times {10^{17}}$$
D. $$4 \times {10^{15}}$$

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