Question
The reaction of propene with $$HOCl\left( {C{l_2} + {H_2}O} \right)$$ proceeds through the intermediate :
A.
$$C{H_3} - CH\left( {OH} \right) - CH_2^ + $$
B.
$$C{H_3} - CHCl - CH_2^ + $$
C.
$$C{H_3} - C{H^ + } - C{H_2} - OH$$
D.
$$C{H_3} - C{H^ + } - C{H_2} - Cl$$
Answer :
$$C{H_3} - C{H^ + } - C{H_2} - Cl$$
Solution :
