The range of a projectile is $$R$$ when the angle of projection is $${40^ \circ }.$$ For the same velocity of projection and range, the other possible angle of projection is
A.
$${45^ \circ }$$
B.
$${50^ \circ }$$
C.
$${60^ \circ }$$
D.
$${40^ \circ }$$
Answer :
$${50^ \circ }$$
Solution :
Horizontal range $$R = \frac{{{u^2}\sin 2\theta }}{g}.$$
Range is same for angle of projection $$\theta $$ and $$\left( {{{90}^ \circ } - \theta } \right).$$
Releted MCQ Question on Basic Physics >> Kinematics
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