Question
The products obtained when chlorine gas reacts with cold and dilute acqueous
$$NaOH$$ are:
A.
$$Cl{O^ - }\,{\text{and}}\,ClO_3^ - $$
B.
$$ClO_2^ - \,{\text{and}}\,ClO_3^ - $$
C.
$$C{l^ - }\,{\text{and}}\,Cl{O^ - }$$
D.
$$C{l^ - }\,{\text{and}}\,ClO_2^ - $$
Answer :
$$C{l^ - }\,{\text{and}}\,Cl{O^ - }$$
Solution :
$$C{l_2} + NaOH \to NaCl + NaClO + {H_2}O$$
[cold and dilute]