The percentage of $$\pi$$-character in the orbitals forming $$P - P$$ bonds in $${P_4}$$ is
A.
25
B.
33
C.
50
D.
75
Answer :
75
Solution :
In $${P_4}$$ ,the $$P - P$$ linkage is formed by $$s{p^3} - s{p^3}$$ hybridised orbital overlapping. So the percentage of $$\pi $$ -character
will be $$75\% $$
Releted MCQ Question on Inorganic Chemistry >> P - Block Elements
Releted Question 1
The reddish brown coloured gas formed when nitric oxide is oxidised by air is