Question
The oxidation number of sulphur in $${S_8},\,{S_2}{F_2},\,{H_2}S$$ respectively, are
A.
$${\text{0, + 1 and }} - 2$$
B.
$${\text{ + 2, + 1 and }} - 2$$
C.
$${\text{0, + 1 and + 2}}$$
D.
$$ - 2,{\text{ + 1 and}} - 2$$
Answer :
$${\text{0, + 1 and }} - 2$$
Solution :
TIPS/Formulae :
(i) Oxidation state of element in its free state is zero.
(ii) Sum of oxidation states of all atoms in compound is zero.
$$\eqalign{
& O.N.\,\,{\text{of}}\,\,S\,\,{\text{in}}\,\,{S_8} = 0;\,\,O.N.\,{\text{of}}\,\,S\,{\text{in}}\,{S_2}{F_2} = + 1; \cr
& O.N.\,\,{\text{of}}\,\,S\,\,{\text{in}}\,{H_2}S = - 2; \cr} $$