Question

The oxidation number of $$S$$  in $$N{a_2}{S_4}{O_6}$$   is

A. +0.5
B. 2.5  
C. +4
D. +6
Answer :   2.5
Solution :
$$\eqalign{ & N{a_2}{S_4}{O_6}:2 + 4x - 12 = 0 \cr & \therefore \,\,x = \frac{{10}}{4} = 2.5 \cr & {\text{Oxidation number of}}\,S = 2.5 \cr} $$

Releted MCQ Question on
Physical Chemistry >> Redox Reaction

Releted Question 1

Which of the following represents a redox reaction?

A. $$NaOH + HCl \to NaCl + {H_2}O$$
B. $$BaC{l_2} + {H_2}S{O_4} \to BaS{O_4} + 2HCl$$
C. $$CuS{O_4} + 2{H_2}O \to Cu{\left( {OH} \right)_2} + {H_2}S{O_4}$$
D. $$Zn + 2HCl \to ZnC{l_2} + {H_2}$$
Releted Question 2

Which reaction involves neither oxidation nor reduction?

A. $$CrO_4^{2 - } \to C{r_2}O_7^{2 - }$$
B. $$Cr \to CrC{l_3}$$
C. $$Na \to N{a^ + }$$
D. $$2{S_2}O_3^{2 - } \to {S_4}O_6^{2 - }$$
Releted Question 3

$$Zn$$  gives $${H_2}$$  gas with $${H_2}S{O_4}$$  and $$HCl$$  but not with $$HN{O_3}$$  because

A. Zn acts as an oxidising agent when it reacts with $$HN{O_3}$$
B. $$HN{O_3}$$  is weaker acid than $${H_2}S{O_4}$$  and $$HCl$$
C. In electrochemical series, $$Zn$$  is above hydrogen
D. $$NO_3^ - $$  is reduced in preference to hydronium $$ion$$
Releted Question 4

A compound of $$Xe$$  and $$F$$  is found to have $$53.5\% $$  of $$Xe.$$  What is oxidation number of $$Xe$$  in this compound ?

A. $$-4$$
B. $$0$$
C. $$+4$$
D. $$+6$$

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Redox Reaction


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